Percentage Problems
Practice aptitude questions on percentages
Question 1:
Two students appeared at an examination. One secured 9 marks more than the other, and his marks were 56% of the total. What are their marks?
Explanation:
Let their marks be **(x + 9)** and **x**.
Since:
(x + 9) = (56/100) × (x + 9 + x)
Multiplying both sides by **100**:
25(x + 9) = 14(2x + 9)
Expanding:
25x + 225 = 28x + 126
3x = 99
x = 33
So, their marks are **42 and 33**.
Final Answer: 42, 33.
Let their marks be **(x + 9)** and **x**.
Since:
(x + 9) = (56/100) × (x + 9 + x)
Multiplying both sides by **100**:
25(x + 9) = 14(2x + 9)
Expanding:
25x + 225 = 28x + 126
3x = 99
x = 33
So, their marks are **42 and 33**.
Final Answer: 42, 33.
Question 2:
If the price of a product is increased by 25%, by what percent should the consumption be reduced to maintain the same expense?
Explanation:
If the price increases by **R%**, the reduction required in consumption is:
(R / (100 + R)) × 100
Substituting **R = 25**:
(25 / 125) × 100 = 20%
Final Answer: 20%.
If the price increases by **R%**, the reduction required in consumption is:
(R / (100 + R)) × 100
Substituting **R = 25**:
(25 / 125) × 100 = 20%
Final Answer: 20%.
Question 3:
If 45% of a number is 315, what is the number?
Explanation:
Let the number be **X**.
45% of X = 315
Solving for X:
X = (315 × 100) / 45
X = 700
Final Answer: 700.
Let the number be **X**.
45% of X = 315
Solving for X:
X = (315 × 100) / 45
X = 700
Final Answer: 700.
Question 4:
What percentage of 200 is 80?
Explanation:
Using the percentage formula:
(80 / 200) × 100
= 40%
Final Answer: 40%.
Using the percentage formula:
(80 / 200) × 100
= 40%
Final Answer: 40%.